Difference between revisions of "Light-emitting diode"

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(LED calculation)
 
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Example a LED with voltage drop of Uled=1.2V and a max current of I_max=0,020A (20mA) to be powered by a 5V DC source needs:
 
Example a LED with voltage drop of Uled=1.2V and a max current of I_max=0,020A (20mA) to be powered by a 5V DC source needs:
  
R = (5-1.2)/.02 = 190 ohm
+
R = (5-1.2)/.02 = 190 ohm
  
 
You then connect a 190 ohm resistance in series with the LED to make it work.
 
You then connect a 190 ohm resistance in series with the LED to make it work.

Revision as of 13:48, 27 July 2007

Light emitting diode:

The resistance required is as follows: R = (U_power - U_led) / I_max

Example a LED with voltage drop of Uled=1.2V and a max current of I_max=0,020A (20mA) to be powered by a 5V DC source needs:

R = (5-1.2)/.02 = 190 ohm

You then connect a 190 ohm resistance in series with the LED to make it work.


http://en.wikipedia.org/wiki/LED